1 #' @title dateIndexToInteger
3 #' @description Transform a (potential) date index into an integer (relative to data)
5 #' @param index Date (or integer) index
6 #' @param data Object of class \code{Data}
9 dateIndexToInteger = function(index, data)
12 if (is.numeric(index))
13 index = as.integer(index)
14 if (is.integer(index))
16 if (inherits(index, "Date") || is.character(index))
18 tryCatch(indexAsDate <- as.Date(index), error=function(e) stop("Unrecognized index format"))
19 #TODO: tz arg to difftime ?
20 integerIndex <- round( as.numeric(
21 difftime(indexAsDate, as.Date(data$getTime(1)[1])) ) ) + 1
22 if (integerIndex >= 1 && integerIndex <= data$getSize())
24 #WARNING: if index>=2 && series start at date >0h, result must be shifted
25 #Convention: if first date asked, return first matching index (i.e.: 1)
27 if (integerIndex >= 2)
29 date1 = as.POSIXlt(data$getTime(1)[1])
30 date2 = as.POSIXlt(data$getTime(2)[1])
31 shift = (date1$year==date2$year && date1$mon==date2$mon && date1$mday==date2$mday)
33 return (integerIndex + shift)
35 stop("Date outside data range")
37 stop("Unrecognized index format")
40 #' @title integerIndexToDate
42 #' @description Transform an integer index to date index (relative to data)
44 #' @param index Date (or integer) index
45 #' @param data Object of class \code{Data}
48 integerIndexToDate = function(index, data)
51 if (is.numeric(index))
52 index = as.integer(index)
53 if (!is.integer(index))
54 stop("'index' should be an integer")
55 as.Date( data$getTime(index)[1] )
58 #' @title getSimilarDaysIndices
60 #' @description Find similar days indices in the past
62 #' @param index Day index (numeric or date)
63 #' @param limit Maximum number of indices to return
64 #' @param same_seaon Should the indices correspond to day in same season?
67 getSimilarDaysIndices = function(index, limit, same_season)
69 index = dateIndexToInteger(index)
71 #TODO: mardi similaire à lundi mercredi jeudi aussi ...etc
74 #take all similar days in recent past
75 nb_days = min( (index-1) %/% 7, limit)
76 return ( rep(index,nb_days) - 7*seq_len(nb_days) )
79 #Look for similar days in similar season (+/- 30 days)
82 while (i >= 1 && length(days) < limit)
87 #look in the "future of the past"
91 #...and in the "past of the past"
97 # TODO: exact computation instead of -364
98 # 364 = closest multiple of 7 to 365 - drift along the years... but not so many years so OK
102 return ( days[1:min(limit,length(days))] )